Question

What are the Covid the vertices of triangle B’T’F’? The initial directions are below ⬇️ in the pic.

Answer 1

We need to find the coordinates of the vertices of triangle B'T'F'. They correspond to a translation of the vertices of triangle BTF, with coordinates:

`\begin{gathered} B(-2,1) \\ \\ T(-2,-1) \\ \\ F(2,2) \end{gathered}`

When we translate a point P(x,y) 5 units to the left and 3 units up, we obtain the point:

`P^(\prime)(x-5,y+3)`

Therefore, the original vertices are transformed as:

`\begin{gathered} B(-2,1)\rightarrow B^(\prime)(-2-5,1+3)=B^(\prime)(-7,4) \\ \\ T(-2,-1)\rightarrow T^(\prime)(-2-5,-1+3)=T^(\prime)(-7,2) \\ \\ F(2,2)\rightarrow F^(\prime)(2-5,2+3)=F^(\prime)(-3,5) \end{gathered}`

Therefore, the vertices of triangle B'T'F' are:

`\begin{gathered} B^(\prime)(-7,4) \\ \\ T^(\prime)(-7,2) \\ \\ F^(\prime)(-3,5) \end{gathered}`