Question

Triangle ABC is similar to triangle WXY (A photo will be provided)

Answer 1

Let x be the length of WX

`(16)/(28)=(x)/(24)\rightarrow x=24\cdot(16)/(28)=(96)/(7)`

let y be the length of YZ. We get

`(16)/(28)=(y)/(14)\rightarrow y=14\cdot(16)/(28)=8`

let z be the length of AD

`(28)/(16)=(z)/(12)\rightarrow z=12\cdot(28)/(16)=21`

let c be the length of DB and d the length of ZX we get

`(21)/(12)=(c)/(d)\rightarrow d\cdot(7)/(4)=c`