Answer:
Maximum speed = 41 mph
Explanation:
Here we see that the speed of wind is increasing by 3 miles per hours. The start time was 9 AM . If we consider it as our starting time i.e h=0 , at 4 PM the value of h will be 7
Hence the speed at various duration will be like this
at
h=0 ; s = 20 Where s is speed of the wind
h=1 ; =23
h=2 ; 26
Let us find the equation from these points , considering h on x asix and s at y axis.
Here for h =0 , s = 20 , hence y intercept is 20
Also
Let us find the slope
slope m is given as

m=3
The slope intercept form of a line is
y=mx+c
putting values of m and c we get
y=3x+20
Now we have to find the speed of wind at h=7 , hence we put x= 7 and h is n x axis
y=3(7)+20
y=21+20
y=41
Hence maximum speed was 41 mph
Now we have to find the time taken to reach the minimum . For which we are supposed to have rate of decrements , which is not given hence we can not find the exact time after which it attains the minimum speed.