Question

Calculate the capacitance of a system that stores 2.0 10-10 C of charge at 100.0 V. Use .

Answer 1

Hi there,
So your answer to your question
A) C=Q/V=(10*10^-6)/10=10^-6 Farads
B)V=Q/C=100*10^-6/10^-6=100 Volts thanks~Becky

Answer 2

Capacitance,
`C=2\ pF`

Step-by-step explanation:

It is given that,

Charge stored in the capacitor,
`q=2* 10^(-10)\ C`

Potential difference, V = 100 V

Capacitance of a system is given by :

`C=(q)/(V)`

`C=(2* 10^(-10)\ C)/(100\ V)`

`C=2* 10^(-12)\ Farad`

or C = 2 picofarad , c = 12 pF

Hence, the capacitance of the system is
`2\ pF`