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The sum of the digits of a two-digit number is 11. When the digits are reversed, the new number is 45 more than the original number. Find the original number. Check your answer.

User Onur
by
3.2k points

1 Answer

17 votes
17 votes

Answer:

Explanation:

Let the 10s digit = x

Let the units digit = y

x +y = 11 Sum of the digits = 11

10x + y + 45 = 10y + x Reversed number is 45 more than original #

10x - x + y + 45 = 10y We subtracted x from both sides.

9x + y + 45 = 10y Subtract y from both sides.

9x + 45 = 10y - y Combine the right

9x + 45 = 9y

Put x + y = 11 into the equation just found.

9x + 45 = 9(11 - x) divide through by 9

x + 45/9 = 11 - x add x to both sides

2x + 5 = 11 Subtract 5 from both sides

2x = 11 - 5

2x = 6 Divide by 2

x = 6/2

x = 3

x + y = 11

3 + y = 11

y = 11 - 3

y = 8

Now check it out.

the original number is 38

the new number is 83 which the digits are reversed.

83 - 38 = 45 just as it should.

User DumP
by
3.2k points
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