Question

Factor the polynomial using the pattern.x^2+ 3x - 18

Answer 1

(x-3)(x+6)

Step-by-step explanation:

Given the polynomial: x²+3x-18

To factor it, first, we multiply the first and last terms.

`-18* x^2=-18x^2`

Next, we list add factors of -18.

`\begin{gathered} -18=-1*18 \\ -18=-2*9 \\ -18=-3*6 \end{gathered}`

Next, we determine the factors that add up to the middle term: 3x

These factors are: 6x and -3x.

Replacing the middle term, we have:

`\begin{gathered} x^2+6x-3x-18 \\ =x(x+6)-3(x+6) \\ =(x-3)(x+6) \end{gathered}`