Question

For the equation f(x)=x^2-2x-15 find the axis of symmetry

Answer 1

Step 1

Given;

`f(x)=x^2-2x-15`

Required; To find the axis of symmetry

Step 2

`\begin{gathered} \mathrm{For\:a\:parabola\:in\:standard\:form}\:y=ax^2+bx+c \\ \mathrm{the\:axis\:of\:symmetry\:is\:the\:vertical\:line\:that\:goes\:through\:the\:vertex}\:x=(-b)/(2a) \\ a=1,b=-2 \end{gathered}`
`\begin{gathered} x=(-\left(-2\right))/(2\cdot \:1) \\ Simplify \\ x=1 \end{gathered}`

Answer;

`\begin{gathered} The\text{ axis of symmetry of f\lparen x\rparen=x}^2-2x-15\text{ is;} \\ x=1 \end{gathered}`