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Answer if you know

this is calculus so don't put idk or whatever
show all work and resons


the reigon R is bounded by the x axis,the y axis and y=√x and y=6-x
the area of the reigon is 22/3
the reigon R is the base of a solid. for every y, where 0≤y≤2, the cross section of the solid taken perpendicular to the y axis is a rectangle whose base lies in R and whose heigh is is 2y. write, but do not evaluate, and integral expression that gives the volume of the solid

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I've attached a plot of one such cross-section (orange) over the region in the x-y plane (blue), including the bounding curves (red). (I've set
y=1.25 for this example.)

The length of each cross section (the side lying in the base) has length determined by the horizontal distance
x between the y-axis
x=0 and the curve
y=\sqrt x. In terms of
y, this distance is
x=y^2. The height of each cross section is twice the value of
y, so the area of each rectangular cross section should be
2y^3.

This means the volume would be given by the integral


\displaystyle\int_0^22y^3\,\mathrm dy
Answer if you know this is calculus so don't put idk or whatever show all work and-example-1
User Jeff Grimes
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