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Find the zeros by using the quadratic formula and tell whether the solutions are real or imaginary. F(x)=x^2+5x+23

User Andrew Jackson
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1 Answer

16 votes
16 votes

Let the function


F(x)=x^2\text{ + 5x + 23}

The quadratic formula is:

So, the zeros of the function F(x)=x^2+5x+23 are the solutions x´s for the equation:


0=x^2\text{ + 5x + 23}

these solutions can be found using the quadratic formula.

Then, we will use the quadratic formula with a = 1, b = 5, and c = 23. That is:

that is equivalent to say:


\frac{-5\text{ +/- }\sqrt[]{25\text{ - 92}}}{2}\text{ = }\frac{-5\text{ +/- }\sqrt[]{-67}}{2}

but


\sqrt[]{-67\text{ }}=\text{ }i\text{ }\sqrt[]{67}

so, we have


\frac{-5\text{ +/- }\sqrt[]{25\text{ - 92}}}{2}\text{ = }\frac{-5\text{ +/- }\sqrt[]{-67}}{2}\text{ = }\frac{-5\text{ +/- }\sqrt[]{67}i}{2}

We can conclude that the zeros for F(x)=x^2+5x+23 are


\text{ }\frac{-5\text{ + }\sqrt[]{67}i}{2}\text{ and }\frac{-5\text{ - }\sqrt[]{67}i}{2}\text{ , those zeros are imaginary numbers.}

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User Marcela
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