Question

The question is attached. I need help with this question

Answer 1

Given the equation of a quadratic function in the form:

`y=ax^2+bx+c`

Equation: y = x² - 6x + 7

where a = 1, b = -6, and c = 7.

Vertex form of a quadratic function:

`y=a\left(x-h\right)^2+k`

where (h, k) is the vertex.

To find (h, k):

`\begin{gathered} h=(-b)/(2a) \\ \\ h=(6)/(2) \\ \\ h=3 \end{gathered}`
`\begin{gathered} k=f(3) \\ k=3²-6(3)+7 \\ k=-2 \end{gathered}`

Vertex = (3, -2)

ANSWER

Vertex form of the quadratic equation:

`y=(x-3)^2-2`