Question

7420 joules of heat is added to an unknown sample with a mass of 1.3 kg. Thetemperature increases by 2.36 °C. What is the material likely made out of?

Answer 1

So, using the formula:

`Q=mc\Delta T`

We could replace the values of the question:

`7420J=1.3Kg\cdot c\cdot2.36C`

Given that "c" is the specific heat of the substance, we could find it solving the previous equation:

`c=(7420J)/(1.3Kg\cdot2.36C)=(2418.51J)/(Kg\cdot C)`

If we look, this specific heat corresponds likely to Glycerine. That's because glycerine has a specific heat equals 2410J/KgC , and this value is extremely similar to the value that we found.