Question

Nickel-63 has half-life of about 96 years. after 336 years,about how many milligrams of an 800 mg sample will remain?

A)14 MG
B)71 MG
C)229 MG
D)656 MG

Answer 1

f=ar^t if the half-life is 96 years...

.5=r^96

ln(.5)=96lnr

ln(.5)/96=lnr

r=e^((ln.5)/96)

f=800e^(336(ln.5)/96)

f=70.71

So about 71mg will remain after 336 years.

Answer 2

71 mg

Explanation:

nickel-63 has half-life of about 96 years. after 336 years

Initial value is 800 mg sample

half life of nickel-63 is 96 years

time given is 336 years

we use half life formula to get the71 mg amount of nickel remains

Final value = initial value (1/2)^(Time /t(half life ))

`final \ value = 800((1)/(2))^{(336)/(96)}`

now simplify it

336/ 96 = 7/2

`final \ value = 800((1)/(2))^{(7)/(2)}`

= 70.7106

so answer is