Question

Find the perimeter of the polygon with the vertices QC -3,2), R(1, 2), S(1, -2), and T -3, -2).The perimeter isunits.

Answer 1

Let's recall that for finding the length of each side of the polygon, we can use the following formula:

`\text{ Distance or length of each side = }\sqrt{(x_{2\text{ }}}-x_1)^2+(y_{2\text{ }}-y_{1\text{ }})^2`
`\text{ Now, we can calculate the length of each side, as follows:}`

The polygon given is REGULAR, so it will be easier to calculate the perimeter.

Side QR = 1 - (-3) = 1 + 3 = 4 (We use only the x values, because y is constant)

Side RS = 2 - -(2) = 2 + 2 = 4 (We use only the y values, because x is constant)

Side ST = 1 - (-3) = 1 + 3 = 4 (We use only the x values, because y is constant)

Side QT = 2 - (-2) = 2 + 2 = 4 (We use only the y values, because x is constant)

`\text{ Perimeter = 4 + 4 + 4 + 4 = 16 units}`