Question

Solve for the interval 2sin(2x)=1

Answer 1

Hello:
2sin(2x)=1
sin(2x)=1/2
sin(2x)=sin(π/6)
(2x= π/6 +2kπ) or ( 2x =π-π/6 +2kπ)....k in Z
(x= π/12 +kπ) or ( x= 5π/12 +kπ )