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an object accelerates from rest, with a constant acceleration of 6.4 m/s^2, what will its velocity be after 7s?
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2 votes
an object accelerates from rest, with a constant acceleration of 6.4 m/s^2, what will its velocity be after 7s?

User Prashant Shirke
by
7.8k points

2 Answers

7 votes
a = v/t
hence v = at
= 6.4 * 7
User Weteef
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8.6k points
5 votes
Using the first kinematic equation,

v(final) = v(inital) + at
v(final) = 0 + (6.4 m/s^2)(7 s)
v(final) = 44.8 m/s
User Lotfi
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7.7k points
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