Question

It is found experimentally that the electric field in a certain region of Earth's atmosphere is directed vertically down. At an altitude of 390 m the field has magnitude 60.0 N/C. At an altitude of 240 m, the magnitude is 100 N/C. Find the net amount of charge contained in a cube 150 m on edge, with horizontal faces at altitudes of 240 and 390 m. Neglect the curvature of Earth.

Answer 1

`q=7.965*10^-^6C`

Step-by-step explanation:

From the question we are told that

Altitude of
`d_1 390m`

Magnitude
`M_1=60.0 N/C`

Altitude of
`d_2=240 m`

Magnitude is
`M_2= 100 N/C`

Distance of cube
`d_c=150 m`

Generally the flux
`\phi` is mathematical given as

`\phi=60(150)^2cos180+100(150)^2*cos0`

`\phi=-9*10^5`

Generally Quantity of charge q is mathematically given as

`q=\varepsilon _0 *\phi`

`q=8.85*10^-^1^2 *9*10^5`

`q=7.965*10^-^6C`