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Zdeslav Vojkovic · Answer 1 · 2023-08-16T01:38:01+0000

Step-by-step explanation

Let it be the events:

• A: A teenager texts while driving.

,

• B: A teenager has a car accident in the first year of driving.

From the word problem, we have:

$\begin{gathered} P(A)=63\%=(63)/(100)=0.63 \\ P(B)=30\%=(30)/(100)=0.3 \\ P(A\cap B)=21\%=(21)/(100)=0.21 \end{gathered}$

The probability that a teenager gets into an accident in the first year of driving, given that he or she texts while driving is:

$\begin{gathered} P(B|A)=(P(B\cap A))/(P(A)) \\ P(B\lvert A)=\frac{P(A\operatorname{\cap}B)}{P(A)} \\ P(B\lvert A)=(0.21)/(0.63) \\ P(B\lvert A)=0.33 \end{gathered}$ Answer

0.33

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