Question

What must be the value of x so that lines a and b are parallel lines cut by transversal f?

The value of x is ? i thought it was 84 but thats wrong

Answer 1

the answer is 22 i did it on ed
and i got it correct

Answer 2

we know that

if the lines a and b are parallel lines cut by transversal f

then

`(6x-36)=96` --------> by alternate exterior angles

solve for x

`(6x-36)=96\\ 6x=96+36\\6x=132\\x=(132/6)\\x=22\ degrees`

therefore

the answer is

the value of x is
`22\ degrees`