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I need help with this practice problem solving This is trigonometry from my ACT prep guide

I need help with this practice problem solving This is trigonometry from my ACT prep-example-1
User Olawale
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1 Answer

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Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:


f(x)=A\cos ((2\pi)/(T)x)+b

In the given case, you have:

A = 4

T = 3π/4

b = -3

By replacing you obtain:


\begin{gathered} f(x)=4\cos ((2\pi)/((3\pi)/(4))x)-3 \\ f(x)=4\cos ((8)/(3)x)-3 \end{gathered}

Hence, the answer is:

f(x) = 4cos(8/3 x) - 3

User Nad Pat
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