Question

Glass has a specific heat of 0.16 calories/gram°C.

1.0 gram of glass will rise 20.0°C when _____ calories of heat are applied

Answer 1

Calories heat added = Mass of glass times temp. increase times specific heat of glass

calories (small calories) = l.0 g x 20 degrees x .16 calories/gm/degree C = 3.2 calories

Answer 2

3.2 calories

Step-by-step explanation:

The state of aggregation of the glass does not change, as its temperature increases, it is a sensible heat, because it depends on its temperature.

The sensible heat formula is

`Q= m.sh.T`

`sh= 0.16(cal)/(g C)`

`m= 1.0 g\\T= 20C`

`Q= 1.0 g.0.16(cal)/(gC) .20C\\ Q= 3.2 cal`

1.0 gram of glass will rise 20.0°C when 3.2 calories of heat are applied