Question

The height of an item falling can be modeling by h^t=-16t^2+h^o. Where h^o is the initial height in feet, and h^t is the height in feet at time t in seconds. If I drop at a height of 18.9 feet,how long will it take the item to hit the ground.A. 2.09B.1.09C.1.19D.0.09

Answer 1

h(t) = -16t^2+h^0

object falls untill height becomes 0, so h(t) =0, h^0 = 18.9feet

0 = -16t^2 + 18.9

-18.9= -16t^2

-18.9/-16 = -16t^2/-16

t^2=1.18125

`\begin{gathered} t\text{ =}\sqrt[]{1.18125} \\ t\text{ = 1.09sec} \end{gathered}`

ANSWER= OPTION B