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the last six days of August 2011 all time records for high temperatures in Austin Texas which of the following values that identifies the mean absolute deviation for these temperatures F. 4G. 107H. 103J. 3.3

the last six days of August 2011 all time records for high temperatures in Austin-example-1
User Ntwrkguru
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1 Answer

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We have to calculate the mean absolute deviation (MAD) for these temperatures.

We can express the MAD as:


\text{MAD}=(1)/(n)\sum ^n_(i=1)|x_i-\barx

So first we have to calculate the mean of the sample. We can do this as:


\bar{x}=(1)/(n)\sum ^n_(i=1)x_i=(1)/(6)(103+110+112+109+105+103)=(1)/(6)\cdot642=107

Now we can calculate the MAD as:


\begin{gathered} \text{MAD}=(1)/(6)(|103-107|+|110-107|+|112-107|+|109-107|+|105-107|+|103-107|) \\ MAD=(1)/(6)(4+3+5+2+2+4) \\ \text{MAD}=(1)/(6)(20) \\ \text{MAD}\approx3.3 \end{gathered}

Answer: The MAD is approximately 3.3.

User Alena
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