a. Write the equation for the combustion of wood (carbon).
C + O₂ -----> CO₂ (balanced)
b. Write the equation for the combustion of sulfur.
S + O₂ -----> SO₂ (balanced)
c. Write the equation for the combustion of steel wool (iron):
Fe + O₂ -----> Fe₂O₃ (unbalanced)
To balance any equation we have to count the amount of each element that we have on each side. If we take a look at the equation we will see that we have 2 atoms of O and 1 atom of Fe on the left side of the equation and 3 atoms of O and 2 atoms of Fe on the right side.
___ Fe + ___ O₂ -----> ____ Fe₂O₃
O: 2 O: 3
Fe: 1 Fe: 2
If we want to balance the O we will have to change two coefficients. The coefficient in front of O₂ must be a 3 and the coefficient in front of Fe₂O₃ must be a 2.
___ Fe + 3 O₂ -----> 2 Fe₂O₃
O: 6 O: 6
Fe: 1 Fe: 4
We balanced the balanced the O with those changes but we also changed the amount of Fe that we have on the right side. Now we have 4 atoms of Fe. To balance it we have to change the coefficient in front of Fe and put a 4 there.
4 Fe + 3 O₂ -----> 2 Fe₂O₃
O: 6 O: 6
Fe: 4 Fe: 4
Now the equation is balanced.
4 Fe + 3 O₂ -----> 2 Fe₂O₃ (balanced)
d. Write the equation for the combustion of hydrogen.
H₂ + O₂ ------> H₂O (unbalanced)
2 H₂ + O₂ -----> 2 H₂O (balanced)
e. Write the equation for the combustion of magnesium.
Mg + O₂ -----> MgO (unbalanced)
2 Mg + O₂ -----> 2 MgO (balanced)