185k views
4 votes
How many Sr2+ ions are in a mole of Sr3(PO4)2

2 Answers

4 votes

Final answer:

There are 3 moles of Sr2+ ions in a mole of Sr3(PO4)2, based on its chemical formula.

Step-by-step explanation:

The question is asking about the number of Sr2+ ions in a mole of Sr3(PO4)2, which is a stoichiometric problem in chemistry. To solve it, look at the chemical formula of the compound, Sr3(PO4)2. The subscript '3' next to Sr denotes that there are three strontium ions (Sr2+) for every formula unit of Sr3(PO4)2. Since one mole of a compound contains Avogadro's number of formula units, one mole of Sr3(PO4)2 will contain 3 moles of Sr2+ ions. Therefore, we can conclude that there are 3 moles of Sr2+ ions in one mole of Sr3(PO4)2.

User Bye
by
8.9k points
2 votes
Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

1 mol Sr3(PO4)2 ( 1 mol Sr2+ / 1 mol Sr3(PO4)2 ) ( 6.022x10^23 ions Sr2+ / 1 mol Sr2+ ) = 6.022x 10^23 Sr2+ ions
User Umer Hassan
by
7.2k points

Related questions

asked Nov 19, 2017 168k views
PLPeeters asked Nov 19, 2017
by PLPeeters
7.8k points
1 answer
5 votes
168k views
asked Feb 2, 2021 97.1k views
Psicopoo asked Feb 2, 2021
by Psicopoo
7.6k points
1 answer
0 votes
97.1k views