Question

What average power is generated by the muscles of a 70.0-kg mountain climber who climbs a summit of height 325 m in 95.0 min?

Answer 1

average power = total work done/time over which work is done
mgh/t ... 70x9.81x325/95x60 Joules per second or Watts

Answer 2

`P = 39.15 W`

Step-by-step explanation:

As we know that rate of work done is given as power

so here when climber will climb up then the work is done against the gravity

So here we can say work done is

`W = mgH`

`W = (70)(9.81)(325)`

`W = 223177.5 J`

now we know that time taken by him to reach at that position is given as

`t = 95 minutes`

`t = 95 * 60`

`t = 5700 s`

so power is given as

`P = (223177.5)/(5700)`

`P = 39.15 W`