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What is the slope of a line that is perpendicular to the line y=-0.25x 3?

User MeyerRJ
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2 Answers

4 votes

Final answer:

The slope of the line y=-0.25x + 3 is -0.25. The slope of the line perpendicular to it is 4.

Step-by-step explanation:

The line given in the question is y = -0.25x + 3. We can determine the slope of this line by comparing it to the standard form of a linear equation: y = mx + b. The slope of the line is represented by the m term, so in this case, the slope is -0.25.

Now, to find the slope of a line perpendicular to this line, we can use the fact that the product of the slopes of two perpendicular lines is always -1. So, the slope of the line perpendicular to y = -0.25x + 3 would be the negative reciprocal of -0.25.

Since the negative reciprocal of -0.25 is 4, the slope of the line perpendicular to y = -0.25x + 3 is 4.

User Jessi
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3 votes
Assuming the equation is y=-0.25x + or minus 3 (doesn't matter)
The perpendicular line is the opposite reciprocal of the slope, therefore the perpendicular line is
y=4x plus or minus and b value.
User Kennet Belenky
by
8.4k points

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