Question

A spring block system undergoes a simple harmonic oscillation with an aeplitode A= 15cm This oscillator performs 30 oscillations in one minute The maximum acceleration of this oscillator is:

Answer 1

We are given the following information

Amplitude = 15 cm = 0.15 m

Frequency = 30 rpm

We are asked to find the maximum acceleration of the oscillator

The maximum acceleration of the oscillator is given by

`a=A\cdot w^2`

Where A is the amplitude and w is the angular frequency.

`\begin{gathered} w=2\pi f \\ w=2\pi((30)/(60))_{} \\ w=\pi \end{gathered}`

`\begin{gathered} a=0.15\cdot(\pi)^2 \\ a=1.48\; (m)/(s^2) \end{gathered}`

Therefore, the maximum acceleration is 1.48 m/s^2