Question

Use the quadratic formula to determine the exact solutions to the equation.

6x^2+4x-3=0

X=_____. Or x=_______

Answer 1

for ax²+bx+c=0

`x= (-b+/- √(b^2-4ac) )/(2a)`

6x²+4x-3=0
a=6
b=4
c=-3

subsitute

`x= (-4+/- √(4^2-4(6)(-3)) )/(2(6))`

`x= (-4+/- √(16+72) )/(12)`

`x= (-4+/- √(88) )/(12)`

`x= (-4+/- 2√(22) )/(12)`

`x= (-2+/- √(22) )/(6)`


`x= (-2+ √(22) )/(6)` or
`x= (-2- √(22) )/(6)`

aprox x=0.448403 or -1.11507

Answer 2

X1=(-2-√22)/6

X2=(-2+√22)/6