Question

A(n)= 3+(n -1)(5)A(2) = 8A(4) = ?I understand how to do the steps however it's still hard for me to do.The example, I looked at was A(n)= A(1) + (n -1)dA(n)=15+(n-1)(4)A(4)=15+(4-1)(4)A(4)=15+(3)(4)A(4)=15+12A(4)=27Still a bit tough.

Answer 1

Step 1:

Write the equation

A(n) = 3 + (n - 1)5

Step 2:

To find A(2)

Compare A(2) with A(n)

You can see that n = 2 for A(2)

Next, substitute n = 2 in A(n) = 3 + (n-1)5 to find A(2)

`\begin{gathered} A(n)\text{ = 3 + (n - 1)5} \\ A(2)\text{ = 3 + (2 - 1) }*\text{ 5} \\ A(2)\text{ = 3 + 1}*5 \\ A(2)\text{ = 3 + 5} \\ A(2)\text{ = 8} \end{gathered}`

Step 3

Let find A(4)

`\begin{gathered} A(n)\text{ = 3 + (n - 1)5} \\ \text{From A(4), n = 4} \\ A(4)\text{ = 3 + ( 4 - 1 ) }*\text{ 5} \\ A(4)\text{ = 3 + 3}*5 \\ A(4)\text{ = 3 + 15} \\ A(4)\text{ = 18} \end{gathered}`

Final answer

A(4) = 18