Question

Find the difference. 9/x^2-9x-6/x^2-81

Answer 1

assuming you mean
`(9)/(x^2-9)- (6)/(x^2-81)`

we need to make denomeoator the same
multiply left fraction by
`(x^2-81)/(x^2-81)` and right fraction by
`(x^2-9)/(x^2-9)`

we get

`(9(x^2-81))/((x^2-81)(x^2-9))- (6(x^2-9))/((x^2-9)(x^2-81))`
add

`(9(x^2-81)-6(x^2-9))/((x^2-81)(x^2-9))`
expand top

`(9x^2-729-6x^2+54)/((x^2-81)(x^2-9))`
simplfiy

`(3x^2-675)/((x^2-81)(x^2-9))`

Answer 2

With Tiger Adding Fractions; {(9/(x^2-9x))-(6/(x^2-81))} Comparing Fractions; ... Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B) ... To calculate equivalent fraction , multiply the Numerator of each fraction, ... hope this helped i guess