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The equation of the line through (2, 3) and (6, 11).is y = mx - 1.

User Kertosis
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1 Answer

23 votes
23 votes

Given:

There are given the points:


(2,3),and,(6,11)

Step-by-step explanation:

According to the question:

We need to find the equation:

So,

To find the equation, first, we need to find the slope of the line:

So,

From the formula of slope:


m=(y_2-y_1)/(x_2-x_1)

Then,


\begin{gathered} m=(y_(2)-y_(1))/(x_(2)-x_(1)) \\ m=(11-3)/(6-2) \\ m=(8)/(4) \\ m=2 \end{gathered}

Now,

From the formula to find the equation of line:


y-y_1=m(x-x_1)

Then,


\begin{gathered} y-y_(1)=m(x-x_(1)) \\ y-3=2(x-2) \\ y-3=2x-4 \\ y=2x-4+3 \\ y=2x-1 \end{gathered}

Final answer:;

Hence, the equation of the line is shown below:


y=2x-1

User John Nelson
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2.8k points