Question

If the sum of the first two of the five consecutive odd integers is 52, what is the sum of the last two integers? Discuss

Answer 1

Given:

If the sum of the first two of the five consecutive odd integers is 52.

The five consecutive odd integers are,

`x,x+2,x+4,x+6,x+8`

The sum of first two consecutive odd integers is 52.

`\begin{gathered} x+x+2=52 \\ 2x+2=52 \\ 2x=52-2 \\ 2x=50 \\ x=(50)/(2) \\ x=25 \end{gathered}`

The five odd integers are,

`\begin{gathered} x=25 \\ x+2=25+2=27 \\ x+4=25+4=29 \\ x+6=25+6=31 \\ x+8=25+8=33 \end{gathered}`

Now, the sum of last two integers is,

`31+33=64`

The sum of the last two integers is 64