Question

What is the relationship between the ratios of sin x° and cos y°?The ratios are opposites (negative six eighths and six eighths).The ratios are both identical (six tenths and six tenths).The ratios are reciprocals (six eighths and eight sixths).The ratios are both negative (negative six tenths and negative six tenths).

Answer 1

The ratios are both identical

Explanation:

See the great explanation above ↑↑↑

Answer 2

The ratios are both identical

1) Examining this right triangle, we can write the following trig rations. In this case, the sine of x and the cosine of y:

`\begin{gathered} \sin(x)=(opposite\:leg\:to\:angle\:x)/(hypotenuse)=(6)/(10) \\ \\ \cos(y)=(adjacent\:leg\:to\:angle\:x)/(hypotenuse)=(6)/(10) \end{gathered}`

2) So, we can tell that both ratios are identical: