Question

If 86.1 g of nitrogen reacts with lithium, how many grams of lithium will react?

Answer 1

Answer: The amount of lithium reacted is 64.0215 grams.

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}` ....(1)

Given mass of nitrogen = 86.1 g

Molar mass of nitrogen = 28 g/mol

Putting values in above equation, we get:

`\text{Moles of nitrogen}=(86.1g)/(28g/mol)=3.075mol`

For the reaction of nitrogen and lithium, the chemical equation follows:

`3Li+N_2\rightarrow Li_3N_2`

By Stoichiometry of the reaction:

1 mole of nitrogen reacts with 3 moles of lithium.

So, 3.075 moles of nitrogen will react with =
`(3)/(1)* 3.075=9.225mol` moles of lithium.

Now, calculating the mass of lithium by using equation 1, we get:

Molar mass of lithium = 6.94 g/mol

Moles of lithium = 9.225 mol

Putting values in equation 1, we get:

`9.225mol=\frac{\text{Mass of lithium}}{6.94g/mol}\\\\\text{Mass of Lithium}=64.0215g`

Hence, the amount of lithium reacted is 64.0215 grams.