Question

A man pushes a 35.2-kilogram box across a frictionless floor with a force of 128 Newtons. What is the acceleration of the box?

Answer 1

3.636 m/s^2

Explanation:

We have the following formula, which is the force formula:

`\begin{gathered} F=m\cdot a \\ m=\text{ mass = 35.2 kg} \\ F=\text{ force = 128 N} \\ a=\text{ acceleration} \end{gathered}`

Replacing and solving for a (acceleration):

`\begin{gathered} 128=35.2\cdot a \\ a=(128)/(35.2) \\ a=3.636m/s^2 \end{gathered}`

Therefore, the acceleration is equal to 3.636 m/s^2