Question

The midpoint of the complex numbers 3 - 12i and 7 + 6i is 5 + bi . What is the value of b?

Answer 1

The midpoint between two complex numbers x+yi and u+vi is given by:

`(x+u)/(2)+(y+v)/(2)i`

Plugging the values of the numbers given we have:

`(3+7)/(2)+(-12+6)/(2)i=(10)/(2)-(6)/(2)i=5-3i`

Therefore the value of b is -3