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Find the lateral area of this squarebased pyramid.10ft10 ft[? ]ft2

Find the lateral area of this squarebased pyramid.10ft10 ft[? ]ft2-example-1
User OzrenTkalcecKrznaric
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1 Answer

18 votes
18 votes

Answer:

The formula used to calculate the lateral area of the square-based pyramid is given below as


A_(lateral)=4* area\text{ of each triangular face}

Step 1:

The area of a triangle is given below as


\begin{gathered} A_(triangle)=(1)/(2)* base* height \\ base=10ft,height=10ft \\ \end{gathered}

By substituting the values, we will have


\begin{gathered} A_(tr\imaginaryI angle)=(1)/(2)* base* he\imaginaryI ght \\ A_{tr\mathrm{i}angle}=(1)/(2)*10ft*10ft \\ A_{tr\mathrm{i}angle}=(100ft^2)/(2) \\ A_{tr\mathrm{i}angle}=50ft^2 \end{gathered}

Step 2:

The lateral area will be


\begin{gathered} A_(lateral)=4* area\text{ of each tr}\imaginaryI\text{angular face} \\ A_(lateral)=4*50ft^2 \\ A_(lateral)=200ft^2 \end{gathered}

Hence,

The final answer = 200ft²

User Mohsin Hasan
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