Question

Find the value of "x"6/19=x-12/2x-2

Answer 1

We are given the following equation:

`(6)/(19)=(x-12)/(2x-2)`

To solve for "x" we will first multiply both sides by 19

`6=(19(x-12))/(2x-2)`

Now we multiply both sides by "2x - 2":

`6(2x-2)=19(x-12)`

Now we solve the operations in the parenthesis using the distributive property:

`12x-12=19x-228`

Now we add 19x on both sides.

`12x-19x-12=-228`

Solving the operations:

`-7x-12=-228`

Adding 12 on both sides:

`-7x-12+12=-228+12`

Solving the operations:

`-7x=-216`

Dividing both sides by -7

`x=-(216)/(-7)`

Solving the operation:

`x=(216)/(7)`

Therefore the value of "x" is 216/7