Question

A car engine operates at 2000 RPM (revolutions per minute). What is the period? Give your answer in seconds

Answer 1

Take into account that the period is the inverse of the frequency. In this case, the frequency is 2000 rev/min, then, you have:

`T=(1)/(f)=(1)/(2000)=0.0005\min`

The period is 0.0005 minutes.

In seconds the answer results in:

0.0005 min = 0.0005*60 seconds = 0.03 seconds

The period is 0.03 seconds