Question

Solve each equation given the indicated root :2x^3 -5x^2 - 4x + 3= 0; 3

Answer 1

Given:

`2x^3-5x^2-4x+3=0`

Required:

To check that 3 is a root of the given equation.

Step-by-step explanation:

Substitute x = 3 in the L.H.S. of the given equation.

`\begin{gathered} 2(3)^3-5(3)^2-4(3)+3 \\ =2(27)-5(9)-12+3 \\ =54-45-12+3 \\ =57-57 \\ =0 \end{gathered}`

This is the R.H.S.

Thus x=3 is a root of the given equatio.

Final Answer:

x= 3 is a root of the given equatio.