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The greatest common factor of 15u2v3, 20u5v2, and 45u3v5 is

User Krul
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2 Answers

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Hello here is a solution :
The greatest common factor of 15u2v3, 20u5v2, and 45u3v5 is : 5u²v²
User Ieisha
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3 votes

Answer:
5u^2v^2

Explanation:

Given monomials :
15u^2v^3, 20u^5v^2, 45u^3v^5

We can rewrite the above monomials as product below :-


15u^2v^3=5*3u^2v^3\\\\ 20u^5v^2=5u^5v^2*4\\\\45u^3v^5=5*9u^3v^5

Therefore, the greatest common factor for numerical coefficients of monomials = 5

Also, the greatest common power of u =2

and the greatest common power of v = 2

Hence, the greatest common factor of
15u^2v^3, 20u^5v^2, 45u^3v^5 is
5u^2v^2

User Timothy Jones
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