Question

A stretched spring has 5184 J of elastic potential energy and a spring constant of 16,200 N/m. What is the displacement of the spring?

Answer 1

Answer:the answer is 0.64 m

Step-by-step explanation:

Answer 2

The elastic potential energy (Ep) is given by
`Ep = (1)/(2)*k*x^2`

Data:
Ep = 5184 J
k = 16200 N/m
x (displacement) = ?

Solving:

`Ep = (1)/(2)*k*x^2`

`5184 = (1)/(2)*16200*x^2`

`5184*2 = 16200x^2`

`10368 = 16200x^2`

`16200x^2 = 10368`

`x^2 = (10638)/(16200)`

`x^2 = 0.64`

`x = √(0.64)`

`\boxed{\boxed{x = 0.8\:m}}\end{array}}\qquad\quad\checkmark`