Question

Please help with this question.n1 = 1, n2 = 1.32, theta1 = 35°, theta2 = ?

Answer 1

In order to calculate the angle of the refracted light, we can use the law of refraction below:

`n_1\sin\theta_1=n_2\sin\theta_2`

So, using the given information, we have:

`\begin{gathered} 1\sin35°=1.32\sin\theta_2\\ \\ 0.5736=1.32\sin\theta_2\\ \\ \sin\theta_2=(0.5736)/(1.32)\\ \\ \sin\theta_2=0.4345\\ \\ \theta_2=25.75° \end{gathered}`

Therefore the angle of the refracted light is 25.75°.