Question

Consider a lightning bolt that carried a current of 13,000 A and transferred a total of 11 C of charge. How long did the lightning bolt last?

Answer 1

8.5 x 10^(-4) s

Step-by-step explanation:

The current I is equal to:

`I=(Q)/(t)`

Where Q is the charge and t is the time. Solving for t, we get:

`t=(Q)/(I)`

So, we need to replace Q = 11C and I = 13,000 A to get:

`t=(11C)/(13,000A)=8.5*10^(-4)s`

Therefore, the lightning bolt lasts 8.5 x 10^(-4) seconds.