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Prove that cosh3x = 4cosh^3(x)-3coshx

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4\cosh^3x-3\cosh x=4\left(\frac{e^x+e^(-x)}2\right)^3-3\frac{e^x+e^(-x)}2

=\frac{(e^x+e^(-x))^3-3(e^x+e^(-x))}2

=\frac{e^(3x)+3e^x+3e^(-x)+e^(-3x)-3e^x-3e^(-x)}2

=\frac{e^(3x)+e^(-3x)}2

=\cosh3x
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