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QuestionEvaluate-6c2 + 2cd + 3d - 4when c = 1 and d =6d - 3+2. Enter an integer or a fraction.Provide your answer below:I need help

User Brian Reischl
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1 Answer

17 votes
17 votes

ok

[-6c(2) + 2cd + 3d - 4] / [6d - 3] Is this correct?

c = 1 d = 2

Substitution

[-6(1)(2) + 2(1)(2) + 3(2) - 4 ] / 6(2) - 3

[-12 + 4 + 6 - 4] / [12 - 3]

[-6] / [9]

-2/3

I think that was the equation

The solution is a fraction: -2/3

User Jakobinsky
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