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consider a pyramid with a height 10 feet in a square base with side lengths 7 feet. How does the volume of the pyramid change if the base stays the same and the height is doubled

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the volume of a pyramid is given by the formula

V= 1/3 x bxh
b= base, since the base is square, so b= L²=49 feet²
h=10feet
so finally V= 1/3x 49x10= 163.33 ft^3

if the height is doubled it means H=2h=20
so the volume is V= 1/3x 49x 20=326.33 ft^3


User Abhishek Mehta
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