Question

A company has increased its number of employees by the same rate each year. How many employees did the company have in 2001?a130b429c546d260

Answer 1

Observe the data given in the table carefully.

Note that each year the number of employees is increased by 13.

This can be obtained by subtracting any number from its succeeding number of employees.

Since the difference is constant, it can be claimed that the number of employees in the years form an arithmetic progression with the common difference (d) as 13.

Let the number of employees in the year 2001 be 'a', and consider it to be the first term in the arithmetic progression.

Using the first data, we can say that after 11 years the number of employees becomes 559. This means that the 11th term of the sequence will be 559.

`\begin{gathered} a_(11)=559 \\ a+(11-1)(13)=559 \\ a+(10)(13)=559 \\ a+130=559 \\ a=559-130 \\ a=429 \end{gathered}`

Thus, the first term of the series, that represents the number of employees in the yea