Question

A 1500 kg car goes from 15 m/s to 29 m/s in 14 s. what is the average force acting upon it.

Answer 1

We have the next information

m=1500 kg

u=15 m/s

v= 29 m/s

t=14 s

First we need to find the acceleration

`a=(v-u)/(t)`

where a is the acceleration, u is the initial velocity, v is the final velocity and t is the time. We substitute the values

`a=(29-15)/(14)=1m/s^2`

Then we use the second Law of Newton

`F=ma`

where F is the force, m is the mass and a is the acceleration.

`F=1500(1)=1500\text{ N}`