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A ballon filled with oxygen occupies a volume of 4.9 L at 30C. What volume will the gas occupy at 199C?

User Alsadk
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1 Answer

1 vote
Data:

V_(initial) = 4.9\:L

T_(initial) = 30^0C
converting to Kelvin
TK = TC + 273
TK = 30 + 273 → TK = 303 →
T_(initial) = 303\:K

V_(final) = ? (in\:liters)

T_(final) = 199^0C
TK = TC + 273
TK = 199 + 273 → TK = 472 →
T_(final) = 472\:K

By the first Law of Charles and Gay-Lussac, we have:

( V_(i) )/( T_(i) ) = ( V_(f) )/( T_(f) )

Solving:

( V_(i) )/( T_(i) ) = ( V_(f) )/( T_(f) )

( 4.9 )/( 303 ) = ( V_(f) )/( 472 )
Product of extremes equals product of means:

303* V_(f) = 4.9*472

303 V_(f) = 2312.8

V_(f) = (2312.8)/(303)

\boxed{\boxed{V_(f) \approx 7.63\:L}}\end{array}}\qquad\quad\checkmark
User Dan Horvat
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